Specific Heat & Cooling Curve — Practice Questions
Free NEET Physics multiple-choice questions on Specific Heat & Cooling Curve. Attempt each question and reveal the answer with a full explanation.
In the determination of the enthalpy of neutralization of HCl and NaOH , the calorimeter is usually a: Polystyrene (Styrofoam) cup Copper beaker Glass flask Iron vessel The enthalpy of neutralization of a strong acid ( HCl ) by a strong base ( NaOH ) is consistently -57.3 kJ/mol . Why is the enthalpy of neutralization lower (less exothermic) when a weak acid like CH 3COOH is used? Some energy is consumed in the complete ionization of the weak acid The weak acid does not react completely with the base The salt formed undergoes extensive hydrolysis The reaction between a weak acid and strong base is endothermic In the determination of specific heat capacity by the method of mixtures, 'water equivalent' of the calorimeter refers to: The mass of water that would absorb the same amount of heat as the calorimeter for the same temperature rise The volume of the calorimeter expressed in liters The density of the material of the calorimeter The heat capacity of the calorimeter divided by the specific heat of the substance According to Newton's Law of Cooling, the time taken for a body to cool from 60 C to 50 C is t 1 , and from 50 C to 40 C is t 2 . If the surrounding temperature is 20 C , then: t 2 > t 1 t 1 > t 2 t 1 = t 2 t 2 = 2t 1 In a calorimetry experiment, 10 g of ice at 0 C is mixed with 10 g of water at 80 C . The final temperature of the mixture is: (Latent heat of fusion = 80 cal/g ) 0 C 40 C 20 C 10 C In Newton's Law of Cooling experiment, if the specific heat of liquid A is greater than liquid B, and both are cooled under identical conditions from 60 C to 50 C : Liquid A will take more time to cool Liquid B will take more time to cool Both will take the same time The time taken depends only on the surrounding temperature In a Newton's Law of Cooling experiment, a student plots a graph between the rate of cooling and the temperature difference. The intercept on the temperature difference axis (where rate = 0) corresponds to: Zero Room temperature Initial temperature of the liquid Boiling point of the liquid In an experiment to verify Newton's Law of Cooling, a graph is plotted between the log of temperature difference (T - T s) and time t . The slope of this graph is equal to: -K / (ms) K / (ms) ms / K 1 / (msK)