Although +3 oxidation state is most common in lanthanoids, cerium still shows +4 oxidation state because:

1. A. After losing one more electron, it acquires 4f 14 electronic configuration.
2. B. Its nearest inert gas is Radon.
3. C. After losing one more electron, it acquires 4f 0 electronic configuration.
4. D. Its atomic number is 61.

Attempt this NEET 2026 Chemistry question free — pick an option to reveal the correct answer and a step-by-step explanation. Then join NEET Mastery Quest to practise 15,000+ PYQ and 2027-syllabus questions.