Consider the following nuclear reaction 238 0 U 234 Th + 4 He . Take masses of 238 U , 234 Th and 4 He as 238.050 u, 234.043 u and 4.003 u, respectively. The Q value for the reaction, in keV, is: [Given: 1 u =931.5 MeV c -2 ]
- A. 3726
- B. 3730
- C. 3736
- D. 3740
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