What mass of 95% pure CaCO3 will be required to neutralise 50 mL of 0.5 M HCl solution according to the following reaction? CaCO3(s) + 2HCl(aq) -> CaCl2(aq) + CO2(g) + 2H2O(l) [Calculate upto second place of decimal point]

1. A. 1.32 g
2. B. 3.65 g
3. C. 9.50 g
4. D. 1.25 g

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