Given below are half cell reactions: MnO4 - + 8H+ + 5e - -> Mn 2+ + 4H2O E Mn 2+/MnO4 - = -1.510 V 1/2 O2 + 2H+ + 2e - -> H2O E O2/H2O = +1.223 V Will the permanganate ion, MnO4 - liberate O2 from water in the presence of an acid?

1. A. No, because E cell =-0.287 V
2. B. Yes, because E cell =+2.733 V
3. C. No, because E cell =-2.733 V
4. D. Yes, because E cell =+0.287 V

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