A thin semicircular conducting ring (PQR) of radius 'r' is falling with its plane vertical in a horizontal magnetic field B, as shown in figure. The potential difference developed across the ring when its speed is v, is :-
- A. Zero
- B. Bv r 2/2 and P is at higher potnetial
- C. rBv and R is at higher potential
- D. 2rBv and R is at higher potential
Attempt this NEET 2014 Physics question free — pick an option to reveal the correct answer and a step-by-step explanation. Then join NEET Mastery Quest to practise 15,000+ PYQ and 2027-syllabus questions.