Steam at 100 C is passed into 20 g of water at 10 C . When water acquires a temperature of 80 C , the mass of water present will be : [Take specific heat of water = 1 cal g -1 C -1 and latent heat of steam = 540 cal g -1 ]
- A. 24 g
- B. 31.5 g
- C. 42.5 g
- D. 22.5 g
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