Given : (i) Cu 2+ + 2e - -> Cu , E =0.337 V (i) Cu 2+ + e - -> Cu + , E =0.153 V Electrode potential E for the reaction, Cu + + e - -> Cu , will be :
- A. 0.38 V
- B. 0.52 V
- C. 0.90 V
- D. 0.30 V
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