If NaCl is doped with 10 -4 mol % of SrCl2 , the concentration of cation vacancies will be ( N A = 6.02 10 23 mol -1 )

1. A. 6.02 10 16 mol -1
2. B. 6.02 10 17 mol -1
3. C. 6.02 10 14 mol -1
4. D. 6.02 10 15 mol -1

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