Electric Field Due To A Uniformly Charged Thin Spherical Shell

Electric Field Due To A Uniformly Charged Thin Spherical Shell — the NEET Physics formula with its derivation, variables, validity constraints and worked solver.

Electric Field due to a Uniformly Charged Thin Spherical Shell Valid only for a uniformly charged thin spherical shell. The charge must be static. Construct a Gaussian surface (sphere) with radius r. For r < R, the enclosed charge q in is 0, therefore E = 0. For r >= R, the enclosed charge q in is Q. Apply Gauss's Law: E (4 pi r 2) = Q / epsilon 0. Solve for E. r must be non-negative R must be positive Inside the shell (r < R), the field is strictly zero due to Gauss's Law cancellation. Assuming the field inside the shell increases with distance (confusing with solid non-conducting sphere). Forgetting that the shell behaves exactly like a point charge for all points outside the shell. Applying this formula to a conducting solid sphere (result is same) vs a non-conducting solid sphere (result differs inside).